[ipok]

То ли лыжи не едут то ли...

1. делаю запрос в договор - получаю ид клиента.
2. делаю запрос в клиента - получаю его имя.
3. создаю новый лукап.

Верно ? или можно шаг 1 и 2 каким - то образом объединить ?

пример запроса в шаге 1 :


// Prepare variables for a contact to retrieve.
var authenticationHeader = GenerateAuthenticationHeader();

// Prepare the SOAP message.
var xml = "<?xml version='1.0' encoding='utf-8'?>"+
"<soap:Envelope xmlns:soap='http://schemas.xmlsoap.org/soap/envelope/'"+
" xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance'"+
" xmlns:xsd='http://www.w3.org/2001/XMLSchema'>"+
authenticationHeader+
"<soap:Body>"+
"<Retrieve xmlns='http://schemas.microsoft.com/crm/2007/WebServices'>"+
"<entityName>new_dogovor</entityName>"+
"<id>"+dogovorid+"</id>"+
"<columnSet xmlns:q1='http://schemas.microsoft.com/crm/2006/Query' xsi:type='q1:ColumnSet'>"+
"<q1:Attributes>"+
"<q1:Attribute>new_bizbizpdogovor</q1:Attribute>"+
"</q1:Attributes>"+
"</columnSet>"+
"</Retrieve>"+
"</soap:Body>"+
"</soap:Envelope>";
// Prepare the xmlHttpObject and send the request.
var xHReq = new ActiveXObject("Msxml2.XMLHTTP");
xHReq.Open("POST", "/mscrmservices/2007/CrmService.asmx", false);
xHReq.setRequestHeader("SOAPAction","http://schemas.microsoft.com/crm/2007/WebServices/Retrieve");
xHReq.setRequestHeader("Content-Type", "text/xml; charset=utf-8");
xHReq.setRequestHeader("Content-Length", xml.length);
xHReq.send(xml);
// Capture the result.
var resultXml = xHReq.responseXML;

// Check for errors.
var errorCount = resultXml.selectNodes('//error').length;
if (errorCount != 0)
{
var msg = resultXml.selectSingleNode('//description').nodeTypedValue;
alert(msg);
}
// Display the retrieved value.
else
{
alert(resultXml.selectSingleNode("//q1:new_bizbizpdogovor").nodeTypedValue);
}